已知:2A AxB=7A A+6B(A.B.均 句为自然数 A>B)a+2b+ab=6,求a+2b最小值.B. 的值?


展开全部先把已知等式转换一下:A*B=6*A+6*B
---》 A=6*B/(B-6)=6+36/(B-6)从上式可以看出,要使A是自然数,则36/(B-6)必须是自然数,也就是36能整除B-6。能被36整除的自然数,有1、2、3、4、6、9、12、18、36。所以,可以逐一检验:B-6=1,则B=7,A=42B-6=2,则B=8,A=24B-6=3,则B=9,A=18B-6=4,则B=10,A=15B-6=6,则B=12,A=12,A=B,不合题意B-6=9,则B=15,A=10B-6=12,则B=18,A=9B-6=18,则B=24,A=8B-6=36,则B=42,A=7所以,共有7组答案。
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