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/etc/nginx/nginx.conf.微信红包随机分 2 包，开出 5：5、6：4、7：3、8：2、9：1 的概率怎么算？
微信红包随机分2包，开出5：5，6：4，7：3，8：2，9：1的概率怎么算？
具体怎么算只有微信才知道你不如发100个1毛分两份的红包，统计一下结果就得到了经验分布。10块线解决问题嗯，自己发自己拿的话还免费
谢邀，本以为一两段话就可以结束，没想到越写越长。微信红包最小的单位是分，所以红包金额可视作离散型的均匀分布：每一种结果等可能。至于每一种结果的概率多少，那就要看总共有多少种结果；并且，因为红包分配规则不会出现一个人全拿，而另一个人不拿，所以要排除掉这种结果，因此结果总数为n-1。每一种结果发生的概率只是其中之一，也就是，1/(n-1)。其中，n随红包总金额的变化而变化——如果红包总额是1毛钱（10分），则结果总数为n-1=9，分别为：1：92：83：74：65：56：47：38：29：1那么题主所说的那几种分配情况，分别对应的概率都是1/9（但若不考虑排列顺序，则张三拿2分李四拿8分以及张三拿8分李四拿2分，都可以看成是2：8。所以更准确地说，除了5：5的概率是1/9，其它分法出现的概率是2/9）。如果红包总额是1元钱（100分），则结果总数n-1=99，则每种组合可能的概率为1/99（不考虑顺序则除了50：50的概率是1/99，其余结果都是2/99）。如果是红包最大金额200元（20,000分），那n-1=19,999，每种组合的可能性是1/19,999（ 不考虑顺序则除了10,000：10,000的概率是1/19,999，其余结果都是2/19,999）。大致如此。
如果是真随机的话,不存在0:10,而且肯定是整数的话,这几个的概率都是20%,五分之一,我不懂微信红宝哈但是没有比如10块钱,有没有4块5和5块5的金额,你这些比例是否恰当
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